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1653400137 = 35310398743
BaseRepresentation
bin110001010001100…
…1110001001001001
311021020011102121010
41202203032021021
511341232301022
6432022034133
755654445364
oct14243161111
94236142533
101653400137
11779334aa4
123a1878949
1320471199c
141198350db
159a24b50c
hex628ce249

1653400137 has 8 divisors (see below), whose sum is σ = 2246128704. Its totient is φ = 1081469168.

The previous prime is 1653400069. The next prime is 1653400163. The reversal of 1653400137 is 7310043561.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1653400137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1653400937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5199213 + ... + 5199530.

It is an arithmetic number, because the mean of its divisors is an integer number (280766088).

Almost surely, 21653400137 is an apocalyptic number.

It is an amenable number.

1653400137 is a deficient number, since it is larger than the sum of its proper divisors (592728567).

1653400137 is a wasteful number, since it uses less digits than its factorization.

1653400137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10398799.

The product of its (nonzero) digits is 7560, while the sum is 30.

The square root of 1653400137 is about 40662.0232772547. The cubic root of 1653400137 is about 1182.4768754706.

Adding to 1653400137 its reverse (7310043561), we get a palindrome (8963443698).

The spelling of 1653400137 in words is "one billion, six hundred fifty-three million, four hundred thousand, one hundred thirty-seven".

Divisors: 1 3 53 159 10398743 31196229 551133379 1653400137