Base | Representation |
---|---|
bin | 11110110100001001… |
… | …00110101101110011 |
3 | 1120200221121000102122 |
4 | 33122010212231303 |
5 | 232340121322011 |
6 | 11333333304455 |
7 | 1123651534154 |
oct | 173204465563 |
9 | 46627530378 |
10 | 16543542131 |
11 | 701a442076 |
12 | 325849512b |
13 | 17385751ac |
14 | b2d21d92b |
15 | 66c5b03db |
hex | 3da126b73 |
16543542131 has 2 divisors, whose sum is σ = 16543542132. Its totient is φ = 16543542130.
The previous prime is 16543542077. The next prime is 16543542137. The reversal of 16543542131 is 13124534561.
It is a strong prime.
It is an emirp because it is prime and its reverse (13124534561) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16543542131 - 222 = 16539347827 is a prime.
It is a super-2 number, since 2×165435421312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16543542091 and 16543542100.
It is not a weakly prime, because it can be changed into another prime (16543542137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8271771065 + 8271771066.
It is an arithmetic number, because the mean of its divisors is an integer number (8271771066).
Almost surely, 216543542131 is an apocalyptic number.
16543542131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16543542131 is an equidigital number, since it uses as much as digits as its factorization.
16543542131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43200, while the sum is 35.
The spelling of 16543542131 in words is "sixteen billion, five hundred forty-three million, five hundred forty-two thousand, one hundred thirty-one".
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