Base | Representation |
---|---|
bin | 10011101110101… |
… | …10000010100001 |
3 | 102112102102121211 |
4 | 21313112002201 |
5 | 314332100022 |
6 | 24231150121 |
7 | 4046516302 |
oct | 1167260241 |
9 | 375372554 |
10 | 165503137 |
11 | 85470a58 |
12 | 47515341 |
13 | 28399567 |
14 | 17da27a9 |
15 | e7e2e77 |
hex | 9dd60a1 |
165503137 has 2 divisors, whose sum is σ = 165503138. Its totient is φ = 165503136.
The previous prime is 165503131. The next prime is 165503159. The reversal of 165503137 is 731305561.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84070561 + 81432576 = 9169^2 + 9024^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-165503137 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 165503099 and 165503108.
It is not a weakly prime, because it can be changed into another prime (165503131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82751568 + 82751569.
It is an arithmetic number, because the mean of its divisors is an integer number (82751569).
Almost surely, 2165503137 is an apocalyptic number.
It is an amenable number.
165503137 is a deficient number, since it is larger than the sum of its proper divisors (1).
165503137 is an equidigital number, since it uses as much as digits as its factorization.
165503137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 31.
The square root of 165503137 is about 12864.8022526582. The cubic root of 165503137 is about 549.0375863309.
Adding to 165503137 its reverse (731305561), we get a palindrome (896808698).
The spelling of 165503137 in words is "one hundred sixty-five million, five hundred three thousand, one hundred thirty-seven".
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