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165623363137913 is a prime number
BaseRepresentation
bin100101101010001000110001…
…101110011111000101111001
3210201102102211221112121022112
4211222020301232133011321
5133202033121430403123
61344130153405102105
746612615223243642
oct4552106156370571
9721372757477275
10165623363137913
114885552377667a
12166aab01257935
1371552a6aab145
142cc82dbd906c9
15142339ca52d78
hex96a231b9f179

165623363137913 has 2 divisors, whose sum is σ = 165623363137914. Its totient is φ = 165623363137912.

The previous prime is 165623363137907. The next prime is 165623363137927. The reversal of 165623363137913 is 319731363326561.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 157231837580944 + 8391525556969 = 12539212^2 + 2896813^2 .

It is an emirp because it is prime and its reverse (319731363326561) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 165623363137913 - 28 = 165623363137657 is a prime.

It is a super-2 number, since 2×1656233631379132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (165623363137933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82811681568956 + 82811681568957.

It is an arithmetic number, because the mean of its divisors is an integer number (82811681568957).

Almost surely, 2165623363137913 is an apocalyptic number.

It is an amenable number.

165623363137913 is a deficient number, since it is larger than the sum of its proper divisors (1).

165623363137913 is an equidigital number, since it uses as much as digits as its factorization.

165623363137913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 33067440, while the sum is 59.

The spelling of 165623363137913 in words is "one hundred sixty-five trillion, six hundred twenty-three billion, three hundred sixty-three million, one hundred thirty-seven thousand, nine hundred thirteen".