Base | Representation |
---|---|
bin | 100101101110000011000100… |
… | …010101001101001010111011 |
3 | 210202101010112102120000111211 |
4 | 211232003010111031022323 |
5 | 133220434020321442021 |
6 | 1344453441130503551 |
7 | 46641211103153164 |
oct | 4556030425151273 |
9 | 722333472500454 |
10 | 165892110734011 |
11 | 489494a37902a2 |
12 | 16733004294bb7 |
13 | 7174735c32b5c |
14 | 2cd73145d676b |
15 | 142a37b69a3e1 |
hex | 96e0c454d2bb |
165892110734011 has 2 divisors, whose sum is σ = 165892110734012. Its totient is φ = 165892110734010.
The previous prime is 165892110733879. The next prime is 165892110734081. The reversal of 165892110734011 is 110437011298561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 165892110734011 - 215 = 165892110701243 is a prime.
It is a super-3 number, since 3×1658921107340113 (a number of 44 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (165892110734081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82946055367005 + 82946055367006.
It is an arithmetic number, because the mean of its divisors is an integer number (82946055367006).
It is a 1-persistent number, because it is pandigital, but 2⋅165892110734011 = 331784221468022 is not.
Almost surely, 2165892110734011 is an apocalyptic number.
165892110734011 is a deficient number, since it is larger than the sum of its proper divisors (1).
165892110734011 is an equidigital number, since it uses as much as digits as its factorization.
165892110734011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 49.
The spelling of 165892110734011 in words is "one hundred sixty-five trillion, eight hundred ninety-two billion, one hundred ten million, seven hundred thirty-four thousand, eleven".
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