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1662331113433 is a prime number
BaseRepresentation
bin11000001100001010101…
…001111100111111011001
312212220202201021010012001
4120030022221330333121
5204213423231112213
63311355300521001
7231046054216564
oct30141251747731
95786681233161
101662331113433
11590a99638581
1222a2073b0161
13c09ac600093
145a6589cb4db
152d3938021dd
hex1830aa7cfd9

1662331113433 has 2 divisors, whose sum is σ = 1662331113434. Its totient is φ = 1662331113432.

The previous prime is 1662331113353. The next prime is 1662331113439. The reversal of 1662331113433 is 3343111332661.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 884809253449 + 777521859984 = 940643^2 + 881772^2 .

It is a cyclic number.

It is not a de Polignac number, because 1662331113433 - 213 = 1662331105241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1662331113392 and 1662331113401.

It is not a weakly prime, because it can be changed into another prime (1662331113439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 831165556716 + 831165556717.

It is an arithmetic number, because the mean of its divisors is an integer number (831165556717).

Almost surely, 21662331113433 is an apocalyptic number.

It is an amenable number.

1662331113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1662331113433 is an equidigital number, since it uses as much as digits as its factorization.

1662331113433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69984, while the sum is 37.

The spelling of 1662331113433 in words is "one trillion, six hundred sixty-two billion, three hundred thirty-one million, one hundred thirteen thousand, four hundred thirty-three".