Base | Representation |
---|---|
bin | 11000010101001101001… |
… | …000001000001011000001 |
3 | 12220211211002012100202112 |
4 | 120111031020020023001 |
5 | 204343312240120101 |
6 | 3320042311425105 |
7 | 231541421443322 |
oct | 30251510101301 |
9 | 5824732170675 |
10 | 1672036254401 |
11 | 59511996a637 |
12 | 230075685195 |
13 | c189819c746 |
14 | 5acd9918449 |
15 | 2d7608696bb |
hex | 1854d2082c1 |
1672036254401 has 2 divisors, whose sum is σ = 1672036254402. Its totient is φ = 1672036254400.
The previous prime is 1672036254391. The next prime is 1672036254407. The reversal of 1672036254401 is 1044526302761.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1181027736001 + 491008518400 = 1086751^2 + 700720^2 .
It is a cyclic number.
It is not a de Polignac number, because 1672036254401 - 230 = 1670962512577 is a prime.
It is a super-3 number, since 3×16720362544013 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1672036254407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 836018127200 + 836018127201.
It is an arithmetic number, because the mean of its divisors is an integer number (836018127201).
Almost surely, 21672036254401 is an apocalyptic number.
It is an amenable number.
1672036254401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1672036254401 is an equidigital number, since it uses as much as digits as its factorization.
1672036254401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 1672036254401 in words is "one trillion, six hundred seventy-two billion, thirty-six million, two hundred fifty-four thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •