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1673292308081 is a prime number
BaseRepresentation
bin11000010110010111111…
…111100101111001110001
312220222001121200111111012
4120112113333211321301
5204403400312324311
63320411101200305
7231614512641362
oct30262777457161
95828047614435
101673292308081
11595703981329
12230366260095
13c1a3848b884
145adb8679b69
152d7d5c7878b
hex18597fe5e71

1673292308081 has 2 divisors, whose sum is σ = 1673292308082. Its totient is φ = 1673292308080.

The previous prime is 1673292307961. The next prime is 1673292308119. The reversal of 1673292308081 is 1808032923761.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 959647507456 + 713644800625 = 979616^2 + 844775^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1673292308081 is a prime.

It is a super-2 number, since 2×16732923080812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1673292308581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 836646154040 + 836646154041.

It is an arithmetic number, because the mean of its divisors is an integer number (836646154041).

Almost surely, 21673292308081 is an apocalyptic number.

It is an amenable number.

1673292308081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1673292308081 is an equidigital number, since it uses as much as digits as its factorization.

1673292308081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 870912, while the sum is 50.

The spelling of 1673292308081 in words is "one trillion, six hundred seventy-three billion, two hundred ninety-two million, three hundred eight thousand, eighty-one".