Base | Representation |
---|---|
bin | 11111001011101000… |
… | …00011110100011001 |
3 | 1121012200021010000111 |
4 | 33211310003310121 |
5 | 233241034001411 |
6 | 11405051404321 |
7 | 1131563112142 |
oct | 174564036431 |
9 | 47180233014 |
10 | 16740531481 |
11 | 7110659093 |
12 | 32b24536a1 |
13 | 176a31703b |
14 | b4b45aac9 |
15 | 67ea22721 |
hex | 3e5d03d19 |
16740531481 has 2 divisors, whose sum is σ = 16740531482. Its totient is φ = 16740531480.
The previous prime is 16740531469. The next prime is 16740531517. The reversal of 16740531481 is 18413504761.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12118707225 + 4621824256 = 110085^2 + 67984^2 .
It is a cyclic number.
It is not a de Polignac number, because 16740531481 - 223 = 16732142873 is a prime.
It is a super-2 number, since 2×167405314812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16740531781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8370265740 + 8370265741.
It is an arithmetic number, because the mean of its divisors is an integer number (8370265741).
Almost surely, 216740531481 is an apocalyptic number.
It is an amenable number.
16740531481 is a deficient number, since it is larger than the sum of its proper divisors (1).
16740531481 is an equidigital number, since it uses as much as digits as its factorization.
16740531481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 16740531481 in words is "sixteen billion, seven hundred forty million, five hundred thirty-one thousand, four hundred eighty-one".
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