Base | Representation |
---|---|
bin | 1111010000010011010100… |
… | …0000000111110000101001 |
3 | 2012101110100211212000100201 |
4 | 3310010311000013300221 |
5 | 4144301031021440423 |
6 | 55401142213232201 |
7 | 3350535022020025 |
oct | 364046500076051 |
9 | 65343324760321 |
10 | 16772736515113 |
11 | 5387306553477 |
12 | 1a6a803632661 |
13 | 94887bccc8b7 |
14 | 41db3a455385 |
15 | 1e146d93d2ad |
hex | f4135007c29 |
16772736515113 has 2 divisors, whose sum is σ = 16772736515114. Its totient is φ = 16772736515112.
The previous prime is 16772736515089. The next prime is 16772736515147. The reversal of 16772736515113 is 31151563727761.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14030807875984 + 2741928639129 = 3745772^2 + 1655877^2 .
It is a cyclic number.
It is not a de Polignac number, because 16772736515113 - 221 = 16772734417961 is a prime.
It is not a weakly prime, because it can be changed into another prime (16772736315113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8386368257556 + 8386368257557.
It is an arithmetic number, because the mean of its divisors is an integer number (8386368257557).
Almost surely, 216772736515113 is an apocalyptic number.
It is an amenable number.
16772736515113 is a deficient number, since it is larger than the sum of its proper divisors (1).
16772736515113 is an equidigital number, since it uses as much as digits as its factorization.
16772736515113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5556600, while the sum is 55.
The spelling of 16772736515113 in words is "sixteen trillion, seven hundred seventy-two billion, seven hundred thirty-six million, five hundred fifteen thousand, one hundred thirteen".
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