Base | Representation |
---|---|
bin | 1001110001110110101… |
… | …1100110110001111011 |
3 | 121001122022211100210012 |
4 | 2130131223212301323 |
5 | 10223031413213333 |
6 | 205102351212135 |
7 | 15065144562413 |
oct | 2343553466173 |
9 | 531568740705 |
10 | 168001694843 |
11 | 65281638a04 |
12 | 2868751704b |
13 | 12ac4c542b8 |
14 | 81ba4dd643 |
15 | 45841bee48 |
hex | 271dae6c7b |
168001694843 has 2 divisors, whose sum is σ = 168001694844. Its totient is φ = 168001694842.
The previous prime is 168001694803. The next prime is 168001694941. The reversal of 168001694843 is 348496100861.
It is a weak prime.
It is an emirp because it is prime and its reverse (348496100861) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-168001694843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 168001694791 and 168001694800.
It is not a weakly prime, because it can be changed into another prime (168001694803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84000847421 + 84000847422.
It is an arithmetic number, because the mean of its divisors is an integer number (84000847422).
Almost surely, 2168001694843 is an apocalyptic number.
168001694843 is a deficient number, since it is larger than the sum of its proper divisors (1).
168001694843 is an equidigital number, since it uses as much as digits as its factorization.
168001694843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 995328, while the sum is 50.
The spelling of 168001694843 in words is "one hundred sixty-eight billion, one million, six hundred ninety-four thousand, eight hundred forty-three".
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