Base | Representation |
---|---|
bin | 11111010110110111… |
… | …10001001011110001 |
3 | 1121110020200211010212 |
4 | 33223123301023301 |
5 | 233434203430433 |
6 | 11422300433505 |
7 | 1134116445155 |
oct | 175333611361 |
9 | 47406624125 |
10 | 16834826993 |
11 | 7159903766 |
12 | 3319b48895 |
13 | 1783a111ba |
14 | b59ba5065 |
15 | 687e4bd48 |
hex | 3eb6f12f1 |
16834826993 has 2 divisors, whose sum is σ = 16834826994. Its totient is φ = 16834826992.
The previous prime is 16834826941. The next prime is 16834827001. The reversal of 16834826993 is 39962843861.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16670166769 + 164660224 = 129113^2 + 12832^2 .
It is a cyclic number.
It is not a de Polignac number, because 16834826993 - 212 = 16834822897 is a prime.
It is a super-2 number, since 2×168348269932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16834826693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8417413496 + 8417413497.
It is an arithmetic number, because the mean of its divisors is an integer number (8417413497).
Almost surely, 216834826993 is an apocalyptic number.
It is an amenable number.
16834826993 is a deficient number, since it is larger than the sum of its proper divisors (1).
16834826993 is an equidigital number, since it uses as much as digits as its factorization.
16834826993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13436928, while the sum is 59.
The spelling of 16834826993 in words is "sixteen billion, eight hundred thirty-four million, eight hundred twenty-six thousand, nine hundred ninety-three".
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