Base | Representation |
---|---|
bin | 11000011111111011000… |
… | …011111001010111100001 |
3 | 12221221112002122102121112 |
4 | 120133323003321113201 |
5 | 210040344321042421 |
6 | 3325224245233105 |
7 | 232426540365416 |
oct | 30377303712741 |
9 | 5857462572545 |
10 | 1683544315361 |
11 | 599a94970117 |
12 | 232347702795 |
13 | c29b044227c |
14 | 5b6ac07c10d |
15 | 2dbd5d1545b |
hex | 187fb0f95e1 |
1683544315361 has 2 divisors, whose sum is σ = 1683544315362. Its totient is φ = 1683544315360.
The previous prime is 1683544315291. The next prime is 1683544315447. The reversal of 1683544315361 is 1635134453861.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1655506822225 + 28037493136 = 1286665^2 + 167444^2 .
It is a cyclic number.
It is not a de Polignac number, because 1683544315361 - 210 = 1683544314337 is a prime.
It is not a weakly prime, because it can be changed into another prime (1683544345361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 841772157680 + 841772157681.
It is an arithmetic number, because the mean of its divisors is an integer number (841772157681).
Almost surely, 21683544315361 is an apocalyptic number.
It is an amenable number.
1683544315361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1683544315361 is an equidigital number, since it uses as much as digits as its factorization.
1683544315361 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3110400, while the sum is 50.
The spelling of 1683544315361 in words is "one trillion, six hundred eighty-three billion, five hundred forty-four million, three hundred fifteen thousand, three hundred sixty-one".
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