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16843911684713 is a prime number
BaseRepresentation
bin1111010100011100011101…
…0111110110001001101001
32012122021002011111020212022
43311013013113312021221
54201432312342402323
655453553004154225
73355634556000101
oct365070727661151
965567064436768
1016843911684713
115404510031893
121a80567b38975
139524b2a56779
1442336d176201
151e32372d24c8
hexf51c75f6269

16843911684713 has 2 divisors, whose sum is σ = 16843911684714. Its totient is φ = 16843911684712.

The previous prime is 16843911684709. The next prime is 16843911684781. The reversal of 16843911684713 is 31748611934861.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16784491284544 + 59420400169 = 4096888^2 + 243763^2 .

It is a cyclic number.

It is not a de Polignac number, because 16843911684713 - 22 = 16843911684709 is a prime.

It is a super-2 number, since 2×168439116847132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (16843911684793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8421955842356 + 8421955842357.

It is an arithmetic number, because the mean of its divisors is an integer number (8421955842357).

Almost surely, 216843911684713 is an apocalyptic number.

It is an amenable number.

16843911684713 is a deficient number, since it is larger than the sum of its proper divisors (1).

16843911684713 is an equidigital number, since it uses as much as digits as its factorization.

16843911684713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20901888, while the sum is 62.

The spelling of 16843911684713 in words is "sixteen trillion, eight hundred forty-three billion, nine hundred eleven million, six hundred eighty-four thousand, seven hundred thirteen".