Base | Representation |
---|---|
bin | 11000100110001110110… |
… | …111111110000011101011 |
3 | 12222121000020202102101012 |
4 | 120212032313332003223 |
5 | 210143233202342412 |
6 | 3332304422214135 |
7 | 233056454000351 |
oct | 30461667760353 |
9 | 5877006672335 |
10 | 1690319184107 |
11 | 5a19511272a4 |
12 | 23371858434b |
13 | c351cc02048 |
14 | 5bb51b537d1 |
15 | 2de809adc22 |
hex | 1898edfe0eb |
1690319184107 has 2 divisors, whose sum is σ = 1690319184108. Its totient is φ = 1690319184106.
The previous prime is 1690319184079. The next prime is 1690319184121. The reversal of 1690319184107 is 7014819130961.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1690319184107 - 234 = 1673139314923 is a prime.
It is a super-2 number, since 2×16903191841072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1690319186107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 845159592053 + 845159592054.
It is an arithmetic number, because the mean of its divisors is an integer number (845159592054).
Almost surely, 21690319184107 is an apocalyptic number.
1690319184107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1690319184107 is an equidigital number, since it uses as much as digits as its factorization.
1690319184107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 50.
The spelling of 1690319184107 in words is "one trillion, six hundred ninety billion, three hundred nineteen million, one hundred eighty-four thousand, one hundred seven".
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