Base | Representation |
---|---|
bin | 11000100111010100010… |
… | …110111010100001011001 |
3 | 12222201000111022010212112 |
4 | 120213110112322201121 |
5 | 210203130120031433 |
6 | 3333020224122105 |
7 | 233130400425044 |
oct | 30472426724131 |
9 | 5881014263775 |
10 | 1691484923993 |
11 | 5a239a162997 |
12 | 2339a2a66335 |
13 | c367758c467 |
14 | 5bc228c5c5b |
15 | 2deececd348 |
hex | 189d45ba859 |
1691484923993 has 2 divisors, whose sum is σ = 1691484923994. Its totient is φ = 1691484923992.
The previous prime is 1691484923987. The next prime is 1691484924037. The reversal of 1691484923993 is 3993294841961.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1606485270784 + 84999653209 = 1267472^2 + 291547^2 .
It is a cyclic number.
It is not a de Polignac number, because 1691484923993 - 26 = 1691484923929 is a prime.
It is a super-2 number, since 2×16914849239932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1691484923593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 845742461996 + 845742461997.
It is an arithmetic number, because the mean of its divisors is an integer number (845742461997).
Almost surely, 21691484923993 is an apocalyptic number.
It is an amenable number.
1691484923993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1691484923993 is an equidigital number, since it uses as much as digits as its factorization.
1691484923993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90699264, while the sum is 68.
The spelling of 1691484923993 in words is "one trillion, six hundred ninety-one billion, four hundred eighty-four million, nine hundred twenty-three thousand, nine hundred ninety-three".
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