Base | Representation |
---|---|
bin | 11111100010001111… |
… | …10010110000010011 |
3 | 1121200220021000011122 |
4 | 33301013302300103 |
5 | 234133121110333 |
6 | 11435550032455 |
7 | 1136355532436 |
oct | 176107626023 |
9 | 47626230148 |
10 | 16930253843 |
11 | 71a8761328 |
12 | 3345aa872b |
13 | 179a7132a9 |
14 | b6872581d |
15 | 6914eb798 |
hex | 3f11f2c13 |
16930253843 has 2 divisors, whose sum is σ = 16930253844. Its totient is φ = 16930253842.
The previous prime is 16930253833. The next prime is 16930253863. The reversal of 16930253843 is 34835203961.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16930253843 - 218 = 16929991699 is a prime.
It is a super-3 number, since 3×169302538433 (a number of 32 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 16930253794 and 16930253803.
It is not a weakly prime, because it can be changed into another prime (16930253833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8465126921 + 8465126922.
It is an arithmetic number, because the mean of its divisors is an integer number (8465126922).
Almost surely, 216930253843 is an apocalyptic number.
16930253843 is a deficient number, since it is larger than the sum of its proper divisors (1).
16930253843 is an equidigital number, since it uses as much as digits as its factorization.
16930253843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 44.
The spelling of 16930253843 in words is "sixteen billion, nine hundred thirty million, two hundred fifty-three thousand, eight hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •