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17005321141 = 130027130783
BaseRepresentation
bin11111101011001100…
…01001101110110101
31121220010111211010221
433311212021232311
5234311330234031
611451231014341
71141256562514
oct176546115665
947803454127
1017005321141
117237073516
12336706a3b1
1317b0137403
14b746a667b
15697dc8a11
hex3f5989bb5

17005321141 has 4 divisors (see below), whose sum is σ = 17005581952. Its totient is φ = 17005060332.

The previous prime is 17005321103. The next prime is 17005321159. The reversal of 17005321141 is 14112350071.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14112350071 = 75291874399.

It is a cyclic number.

It is not a de Polignac number, because 17005321141 - 215 = 17005288373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (17005321441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64636 + ... + 195418.

It is an arithmetic number, because the mean of its divisors is an integer number (4251395488).

Almost surely, 217005321141 is an apocalyptic number.

It is an amenable number.

17005321141 is a deficient number, since it is larger than the sum of its proper divisors (260811).

17005321141 is a wasteful number, since it uses less digits than its factorization.

17005321141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260810.

The product of its (nonzero) digits is 840, while the sum is 25.

The spelling of 17005321141 in words is "seventeen billion, five million, three hundred twenty-one thousand, one hundred forty-one".

Divisors: 1 130027 130783 17005321141