Base | Representation |
---|---|
bin | 11000110000010001100… |
… | …010011111100011001011 |
3 | 20000121211200012212022102 |
4 | 120300101202133203023 |
5 | 210332323413212021 |
6 | 3341250344344015 |
7 | 233620606336304 |
oct | 30602142374313 |
9 | 6017750185272 |
10 | 1701101304011 |
11 | 5a648437a59a |
12 | 23582747500b |
13 | c454a951b55 |
14 | 5c495b097ab |
15 | 2e3b236100b |
hex | 18c1189f8cb |
1701101304011 has 2 divisors, whose sum is σ = 1701101304012. Its totient is φ = 1701101304010.
The previous prime is 1701101303971. The next prime is 1701101304017. The reversal of 1701101304011 is 1104031011071.
It is a strong prime.
It is an emirp because it is prime and its reverse (1104031011071) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1701101304011 - 210 = 1701101302987 is a prime.
It is not a weakly prime, because it can be changed into another prime (1701101304017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850550652005 + 850550652006.
It is an arithmetic number, because the mean of its divisors is an integer number (850550652006).
Almost surely, 21701101304011 is an apocalyptic number.
1701101304011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1701101304011 is an equidigital number, since it uses as much as digits as its factorization.
1701101304011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 1701101304011 its reverse (1104031011071), we get a palindrome (2805132315082).
The spelling of 1701101304011 in words is "one trillion, seven hundred one billion, one hundred one million, three hundred four thousand, eleven".
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