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17012607113 is a prime number
BaseRepresentation
bin11111101100000011…
…11100100010001001
31121220122012222121202
433312001330202021
5234320211411423
611452051113545
71141405526435
oct176601744211
947818188552
1017012607113
11724019a587
1233695a28b5
1317b17b8838
14b756419c5
15698867728
hex3f607c889

17012607113 has 2 divisors, whose sum is σ = 17012607114. Its totient is φ = 17012607112.

The previous prime is 17012607109. The next prime is 17012607119. The reversal of 17012607113 is 31170621071.

17012607113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17012506624 + 100489 = 130432^2 + 317^2 .

It is an emirp because it is prime and its reverse (31170621071) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 17012607113 - 22 = 17012607109 is a prime.

It is not a weakly prime, because it can be changed into another prime (17012607119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8506303556 + 8506303557.

It is an arithmetic number, because the mean of its divisors is an integer number (8506303557).

Almost surely, 217012607113 is an apocalyptic number.

It is an amenable number.

17012607113 is a deficient number, since it is larger than the sum of its proper divisors (1).

17012607113 is an equidigital number, since it uses as much as digits as its factorization.

17012607113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1764, while the sum is 29.

The spelling of 17012607113 in words is "seventeen billion, twelve million, six hundred seven thousand, one hundred thirteen".