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1701382527113 is a prime number
BaseRepresentation
bin11000110000100010010…
…011010001100010001001
320000122120021101110212212
4120300202103101202021
5210333412411331423
63341334312114505
7233630562602603
oct30604223214211
96018507343785
101701382527113
115a6609099685
122358a5695a35
13c4593ca7159
145c4c11d2173
152e3cbdb1578
hex18c224d1889

1701382527113 has 2 divisors, whose sum is σ = 1701382527114. Its totient is φ = 1701382527112.

The previous prime is 1701382527079. The next prime is 1701382527121. The reversal of 1701382527113 is 3117252831071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1686432085129 + 14950441984 = 1298627^2 + 122272^2 .

It is a cyclic number.

It is not a de Polignac number, because 1701382527113 - 26 = 1701382527049 is a prime.

It is a super-2 number, since 2×17013825271132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1701382517113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850691263556 + 850691263557.

It is an arithmetic number, because the mean of its divisors is an integer number (850691263557).

Almost surely, 21701382527113 is an apocalyptic number.

It is an amenable number.

1701382527113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1701382527113 is an equidigital number, since it uses as much as digits as its factorization.

1701382527113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70560, while the sum is 41.

The spelling of 1701382527113 in words is "one trillion, seven hundred one billion, three hundred eighty-two million, five hundred twenty-seven thousand, one hundred thirteen".