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17041123657553 is a prime number
BaseRepresentation
bin1111011111111011001000…
…0111110100011101010001
32020100010010012121111002112
43313332302013310131101
54213200210124020203
6100124330101155105
73406115634053042
oct367766207643521
966303105544075
1017041123657553
115480111052a06
121ab28259bba95
13967c8157b218
1442cb1ac6c8c9
151e842aad46d8
hexf7fb21f4751

17041123657553 has 2 divisors, whose sum is σ = 17041123657554. Its totient is φ = 17041123657552.

The previous prime is 17041123657513. The next prime is 17041123657567. The reversal of 17041123657553 is 35575632114071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15055820113489 + 1985303544064 = 3880183^2 + 1409008^2 .

It is a cyclic number.

It is not a de Polignac number, because 17041123657553 - 218 = 17041123395409 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (17041123657513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8520561828776 + 8520561828777.

It is an arithmetic number, because the mean of its divisors is an integer number (8520561828777).

Almost surely, 217041123657553 is an apocalyptic number.

It is an amenable number.

17041123657553 is a deficient number, since it is larger than the sum of its proper divisors (1).

17041123657553 is an equidigital number, since it uses as much as digits as its factorization.

17041123657553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2646000, while the sum is 50.

The spelling of 17041123657553 in words is "seventeen trillion, forty-one billion, one hundred twenty-three million, six hundred fifty-seven thousand, five hundred fifty-three".