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1711325626057 is a prime number
BaseRepresentation
bin11000111001110010111…
…101001011111011001001
320001121020020002020102201
4120321302331023323021
5211014243330013212
63350101103200201
7234432146545345
oct30716275137311
96047206066381
101711325626057
115aa85077a023
122377bb5a6061
13c54b9c61058
145cb85982625
152e7aec7eb57
hex18e72f4bec9

1711325626057 has 2 divisors, whose sum is σ = 1711325626058. Its totient is φ = 1711325626056.

The previous prime is 1711325626037. The next prime is 1711325626081. The reversal of 1711325626057 is 7506265231171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1704536525241 + 6789100816 = 1305579^2 + 82396^2 .

It is a cyclic number.

It is not a de Polignac number, because 1711325626057 - 27 = 1711325625929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1711325625998 and 1711325626016.

It is not a weakly prime, because it can be changed into another prime (1711325626037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 855662813028 + 855662813029.

It is an arithmetic number, because the mean of its divisors is an integer number (855662813029).

Almost surely, 21711325626057 is an apocalyptic number.

It is an amenable number.

1711325626057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1711325626057 is an equidigital number, since it uses as much as digits as its factorization.

1711325626057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 529200, while the sum is 46.

The spelling of 1711325626057 in words is "one trillion, seven hundred eleven billion, three hundred twenty-five million, six hundred twenty-six thousand, fifty-seven".