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17113304497 is a prime number
BaseRepresentation
bin11111111000000100…
…00100110110110001
31122011122200221110111
433330002010312301
5240022001220442
611510045301321
71144040455012
oct177402046661
948148627414
1017113304497
117292017a63
123397264841
1317c96148a3
14b84b75009
156a2608b17
hex3fc084db1

17113304497 has 2 divisors, whose sum is σ = 17113304498. Its totient is φ = 17113304496.

The previous prime is 17113304489. The next prime is 17113304513. The reversal of 17113304497 is 79440331171.

17113304497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13319237281 + 3794067216 = 115409^2 + 61596^2 .

It is a cyclic number.

It is not a de Polignac number, because 17113304497 - 23 = 17113304489 is a prime.

It is not a weakly prime, because it can be changed into another prime (17119304497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8556652248 + 8556652249.

It is an arithmetic number, because the mean of its divisors is an integer number (8556652249).

Almost surely, 217113304497 is an apocalyptic number.

It is an amenable number.

17113304497 is a deficient number, since it is larger than the sum of its proper divisors (1).

17113304497 is an equidigital number, since it uses as much as digits as its factorization.

17113304497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63504, while the sum is 40.

The spelling of 17113304497 in words is "seventeen billion, one hundred thirteen million, three hundred four thousand, four hundred ninety-seven".