Base | Representation |
---|---|
bin | 11111111000000100… |
… | …00111001011011011 |
3 | 1122011122201102111212 |
4 | 33330002013023123 |
5 | 240022002022021 |
6 | 11510045413335 |
7 | 1144040524523 |
oct | 177402071333 |
9 | 48148642455 |
10 | 17113314011 |
11 | 7292024122 |
12 | 339726a24b |
13 | 17c9619011 |
14 | b84b78683 |
15 | 6a260b85b |
hex | 3fc0872db |
17113314011 has 2 divisors, whose sum is σ = 17113314012. Its totient is φ = 17113314010.
The previous prime is 17113313989. The next prime is 17113314017. The reversal of 17113314011 is 11041331171.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 17113314011 - 26 = 17113313947 is a prime.
It is not a weakly prime, because it can be changed into another prime (17113314017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8556657005 + 8556657006.
It is an arithmetic number, because the mean of its divisors is an integer number (8556657006).
Almost surely, 217113314011 is an apocalyptic number.
17113314011 is a deficient number, since it is larger than the sum of its proper divisors (1).
17113314011 is an equidigital number, since it uses as much as digits as its factorization.
17113314011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 17113314011 its reverse (11041331171), we get a palindrome (28154645182).
The spelling of 17113314011 in words is "seventeen billion, one hundred thirteen million, three hundred fourteen thousand, eleven".
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