Base | Representation |
---|---|
bin | 1111100100001010110010… |
… | …0001111111110010000111 |
3 | 2020121002100011122221210021 |
4 | 3321002230201333302013 |
5 | 4220344030320103143 |
6 | 100222030003440011 |
7 | 3414306654230350 |
oct | 371025441776207 |
9 | 66532304587707 |
10 | 17114044300423 |
11 | 54a9030933214 |
12 | 1b04996986007 |
13 | 971b02b13505 |
14 | 432477710d27 |
15 | 1ea297810ced |
hex | f90ac87fc87 |
17114044300423 has 4 divisors (see below), whose sum is σ = 19558907771920. Its totient is φ = 14669180828928.
The previous prime is 17114044300373. The next prime is 17114044300427. The reversal of 17114044300423 is 32400344041171.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 17114044300423 - 241 = 14915021044871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (17114044300427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1222431735738 + ... + 1222431735751.
It is an arithmetic number, because the mean of its divisors is an integer number (4889726942980).
Almost surely, 217114044300423 is an apocalyptic number.
17114044300423 is a deficient number, since it is larger than the sum of its proper divisors (2444863471497).
17114044300423 is an equidigital number, since it uses as much as digits as its factorization.
17114044300423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2444863471496.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 17114044300423 its reverse (32400344041171), we get a palindrome (49514388341594).
The spelling of 17114044300423 in words is "seventeen trillion, one hundred fourteen billion, forty-four million, three hundred thousand, four hundred twenty-three".
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