Base | Representation |
---|---|
bin | 11111111000001100… |
… | …11000101001001010 |
3 | 1122011201211100000110 |
4 | 33330012120221022 |
5 | 240022243342442 |
6 | 11510125415150 |
7 | 1144053201252 |
oct | 177406305112 |
9 | 48151740013 |
10 | 17114434122 |
11 | 7292719735 |
12 | 339770a4b6 |
13 | 17c991bac6 |
14 | b84d8a962 |
15 | 6a277d69c |
hex | 3fc198a4a |
17114434122 has 16 divisors (see below), whose sum is σ = 34359019200. Its totient is φ = 5683119552.
The previous prime is 17114434111. The next prime is 17114434133. The reversal of 17114434122 is 22143441171.
17114434122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (17114434111) and next prime (17114434133).
It is a self number, because there is not a number n which added to its sum of digits gives 17114434122.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5421247 + ... + 5424402.
It is an arithmetic number, because the mean of its divisors is an integer number (2147438700).
Almost surely, 217114434122 is an apocalyptic number.
17114434122 is an abundant number, since it is smaller than the sum of its proper divisors (17244585078).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
17114434122 is a wasteful number, since it uses less digits than its factorization.
17114434122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10845917.
The product of its digits is 5376, while the sum is 30.
Adding to 17114434122 its reverse (22143441171), we get a palindrome (39257875293).
The spelling of 17114434122 in words is "seventeen billion, one hundred fourteen million, four hundred thirty-four thousand, one hundred twenty-two".
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