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17123013889 is a prime number
BaseRepresentation
bin11111111001001110…
…00111010100000001
31122012022222020020121
433330213013110001
5240031442421024
611511033340241
71144216134202
oct177447072401
948168866217
1017123013889
117297549853
12339a567681
1317cb6340a7
14b861815a9
156a33c58e4
hex3fc9c7501

17123013889 has 2 divisors, whose sum is σ = 17123013890. Its totient is φ = 17123013888.

The previous prime is 17123013781. The next prime is 17123013913. The reversal of 17123013889 is 98831032171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16541818225 + 581195664 = 128615^2 + 24108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17123013889 is a prime.

It is not a weakly prime, because it can be changed into another prime (17123011889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8561506944 + 8561506945.

It is an arithmetic number, because the mean of its divisors is an integer number (8561506945).

Almost surely, 217123013889 is an apocalyptic number.

It is an amenable number.

17123013889 is a deficient number, since it is larger than the sum of its proper divisors (1).

17123013889 is an equidigital number, since it uses as much as digits as its factorization.

17123013889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 43.

The spelling of 17123013889 in words is "seventeen billion, one hundred twenty-three million, thirteen thousand, eight hundred eighty-nine".