Base | Representation |
---|---|
bin | 1001111110000001100… |
… | …1001000011001101111 |
3 | 121101001222201122002022 |
4 | 2133200121020121233 |
5 | 10301224203041233 |
6 | 210402444220355 |
7 | 15242122312262 |
oct | 2374031103157 |
9 | 541058648068 |
10 | 171268408943 |
11 | 666a8608625 |
12 | 2923953a6bb |
13 | 131c5980b18 |
14 | 840a2d2cd9 |
15 | 46c5d9a398 |
hex | 27e064866f |
171268408943 has 4 divisors (see below), whose sum is σ = 171745480080. Its totient is φ = 170791337808.
The previous prime is 171268408937. The next prime is 171268408973. The reversal of 171268408943 is 349804862171.
171268408943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-171268408943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (171268408973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238535030 + ... + 238535747.
It is an arithmetic number, because the mean of its divisors is an integer number (42936370020).
Almost surely, 2171268408943 is an apocalyptic number.
171268408943 is a deficient number, since it is larger than the sum of its proper divisors (477071137).
171268408943 is an equidigital number, since it uses as much as digits as its factorization.
171268408943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 477071136.
The product of its (nonzero) digits is 2322432, while the sum is 53.
The spelling of 171268408943 in words is "one hundred seventy-one billion, two hundred sixty-eight million, four hundred eight thousand, nine hundred forty-three".
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