Base | Representation |
---|---|
bin | 11111111010000011… |
… | …11111100100001001 |
3 | 1122012211020012202012 |
4 | 33331001333210021 |
5 | 240040243410131 |
6 | 11511444345305 |
7 | 1144333052003 |
oct | 177501774411 |
9 | 48184205665 |
10 | 17130060041 |
11 | 72a0521716 |
12 | 33a09a5235 |
13 | 17ccc30303 |
14 | b87097373 |
15 | 6a3d1852b |
hex | 3fd07f909 |
17130060041 has 2 divisors, whose sum is σ = 17130060042. Its totient is φ = 17130060040.
The previous prime is 17130060023. The next prime is 17130060053. The reversal of 17130060041 is 14006003171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13082555641 + 4047504400 = 114379^2 + 63620^2 .
It is an emirp because it is prime and its reverse (14006003171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17130060041 - 26 = 17130059977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 17130059989 and 17130060016.
It is not a weakly prime, because it can be changed into another prime (17130060341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8565030020 + 8565030021.
It is an arithmetic number, because the mean of its divisors is an integer number (8565030021).
Almost surely, 217130060041 is an apocalyptic number.
It is an amenable number.
17130060041 is a deficient number, since it is larger than the sum of its proper divisors (1).
17130060041 is an equidigital number, since it uses as much as digits as its factorization.
17130060041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
The spelling of 17130060041 in words is "seventeen billion, one hundred thirty million, sixty thousand, forty-one".
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