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17130314642 = 272174799129
BaseRepresentation
bin11111111010000101…
…11101101110010010
31122012211201010222212
433331002331232102
5240040330032032
611511454032122
71144335162200
oct177502755622
948184633885
1017130314642
1172a0685a31
1233a0aa8642
1317cccbc16c
14b87122070
156a3d68bb2
hex3fd0bdb92

17130314642 has 12 divisors (see below), whose sum is σ = 29890651230. Its totient is φ = 7341563376.

The previous prime is 17130314629. The next prime is 17130314659. The reversal of 17130314642 is 24641303171.

It can be written as a sum of positive squares in only one way, i.e., 17129312641 + 1002001 = 130879^2 + 1001^2 .

It is a super-4 number, since 4×171303146424 (a number of 42 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 17130314599 and 17130314608.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 87399467 + ... + 87399662.

Almost surely, 217130314642 is an apocalyptic number.

17130314642 is a deficient number, since it is larger than the sum of its proper divisors (12760336588).

17130314642 is a wasteful number, since it uses less digits than its factorization.

17130314642 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174799145 (or 174799138 counting only the distinct ones).

The product of its (nonzero) digits is 12096, while the sum is 32.

The spelling of 17130314642 in words is "seventeen billion, one hundred thirty million, three hundred fourteen thousand, six hundred forty-two".

Divisors: 1 2 7 14 49 98 174799129 349598258 1223593903 2447187806 8565157321 17130314642