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171347311441 is a prime number
BaseRepresentation
bin1001111110010100011…
…0000111101101010001
3121101021111012021222001
42133211012013231101
510301404402431231
6210414343314001
715244101054565
oct2374506075521
9541244167861
10171347311441
11667390aa1a9
122925ba4b901
13132091187a7
1484169916a5
1546ccc83b61
hex27e5187b51

171347311441 has 2 divisors, whose sum is σ = 171347311442. Its totient is φ = 171347311440.

The previous prime is 171347311433. The next prime is 171347311519. The reversal of 171347311441 is 144113743171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 158460521041 + 12886790400 = 398071^2 + 113520^2 .

It is an emirp because it is prime and its reverse (144113743171) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 171347311441 - 23 = 171347311433 is a prime.

It is a super-2 number, since 2×1713473114412 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 171347311441.

It is not a weakly prime, because it can be changed into another prime (171347311841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85673655720 + 85673655721.

It is an arithmetic number, because the mean of its divisors is an integer number (85673655721).

Almost surely, 2171347311441 is an apocalyptic number.

It is an amenable number.

171347311441 is a deficient number, since it is larger than the sum of its proper divisors (1).

171347311441 is an equidigital number, since it uses as much as digits as its factorization.

171347311441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28224, while the sum is 37.

The spelling of 171347311441 in words is "one hundred seventy-one billion, three hundred forty-seven million, three hundred eleven thousand, four hundred forty-one".