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1713552312137 is a prime number
BaseRepresentation
bin11000111011110111101…
…011010100011101001001
320001210222101222121111112
4120323313223110131021
5211033323342442022
63351110044540105
7234541265221451
oct30736753243511
96053871877445
101713552312137
11600793676256
12238121251635
13c5783377193
145cd175a8d61
152e8904bd8e2
hex18ef7ad4749

1713552312137 has 2 divisors, whose sum is σ = 1713552312138. Its totient is φ = 1713552312136.

The previous prime is 1713552312133. The next prime is 1713552312149. The reversal of 1713552312137 is 7312132553171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1244962776841 + 468589535296 = 1115779^2 + 684536^2 .

It is a cyclic number.

It is not a de Polignac number, because 1713552312137 - 22 = 1713552312133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1713552312094 and 1713552312103.

It is not a weakly prime, because it can be changed into another prime (1713552312133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 856776156068 + 856776156069.

It is an arithmetic number, because the mean of its divisors is an integer number (856776156069).

Almost surely, 21713552312137 is an apocalyptic number.

It is an amenable number.

1713552312137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1713552312137 is an equidigital number, since it uses as much as digits as its factorization.

1713552312137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 132300, while the sum is 41.

The spelling of 1713552312137 in words is "one trillion, seven hundred thirteen billion, five hundred fifty-two million, three hundred twelve thousand, one hundred thirty-seven".