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17145402002243 is a prime number
BaseRepresentation
bin1111100101111111100110…
…0110001000101101000011
32020201002021112201020220222
43321133321212020231003
54221402240403032433
6100244253340053255
73416500021262504
oct371377146105503
966632245636828
1017145402002243
1155103624a5769
121b0aa8853422b
13974a5c567468
14433bb01babab
151eaed0726b98
hexf97f9988b43

17145402002243 has 2 divisors, whose sum is σ = 17145402002244. Its totient is φ = 17145402002242.

The previous prime is 17145402002161. The next prime is 17145402002249. The reversal of 17145402002243 is 34220020454171.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 17145402002243 - 210 = 17145402001219 is a prime.

It is not a weakly prime, because it can be changed into another prime (17145402002249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8572701001121 + 8572701001122.

It is an arithmetic number, because the mean of its divisors is an integer number (8572701001122).

Almost surely, 217145402002243 is an apocalyptic number.

17145402002243 is a deficient number, since it is larger than the sum of its proper divisors (1).

17145402002243 is an equidigital number, since it uses as much as digits as its factorization.

17145402002243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 53760, while the sum is 35.

The spelling of 17145402002243 in words is "seventeen trillion, one hundred forty-five billion, four hundred two million, two thousand, two hundred forty-three".