Base | Representation |
---|---|
bin | 11000111101001011110… |
… | …000011010000100110001 |
3 | 20001221121201022112012021 |
4 | 120331023300122010301 |
5 | 211044221002311032 |
6 | 3351502035231441 |
7 | 234621244255036 |
oct | 30751360320461 |
9 | 6057551275167 |
10 | 1714962932017 |
11 | 601347958905 |
12 | 238455748581 |
13 | c59496a36ba |
14 | 5d00ca8338d |
15 | 2e924260097 |
hex | 18f4bc1a131 |
1714962932017 has 2 divisors, whose sum is σ = 1714962932018. Its totient is φ = 1714962932016.
The previous prime is 1714962932009. The next prime is 1714962932113. The reversal of 1714962932017 is 7102392694171.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1472706029601 + 242256902416 = 1213551^2 + 492196^2 .
It is a cyclic number.
It is not a de Polignac number, because 1714962932017 - 23 = 1714962932009 is a prime.
It is not a weakly prime, because it can be changed into another prime (1714962902017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 857481466008 + 857481466009.
It is an arithmetic number, because the mean of its divisors is an integer number (857481466009).
Almost surely, 21714962932017 is an apocalyptic number.
It is an amenable number.
1714962932017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1714962932017 is an equidigital number, since it uses as much as digits as its factorization.
1714962932017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1143072, while the sum is 52.
The spelling of 1714962932017 in words is "one trillion, seven hundred fourteen billion, nine hundred sixty-two million, nine hundred thirty-two thousand, seventeen".
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