Base | Representation |
---|---|
bin | 1010000001101001100… |
… | …0000101101010111011 |
3 | 121110120210020020221101 |
4 | 2200122120011222323 |
5 | 10310222222323024 |
6 | 211043154552231 |
7 | 15305204110111 |
oct | 2403230055273 |
9 | 543523206841 |
10 | 172241214139 |
11 | 67057747565 |
12 | 2946b298677 |
13 | 1331c388ab7 |
14 | 849d5a1ab1 |
15 | 47314a8c44 |
hex | 281a605abb |
172241214139 has 2 divisors, whose sum is σ = 172241214140. Its totient is φ = 172241214138.
The previous prime is 172241214127. The next prime is 172241214157. The reversal of 172241214139 is 931412142271.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 172241214139 - 27 = 172241214011 is a prime.
It is a super-2 number, since 2×1722412141392 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 172241214098 and 172241214107.
It is not a weakly prime, because it can be changed into another prime (172241214109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86120607069 + 86120607070.
It is an arithmetic number, because the mean of its divisors is an integer number (86120607070).
Almost surely, 2172241214139 is an apocalyptic number.
172241214139 is a deficient number, since it is larger than the sum of its proper divisors (1).
172241214139 is an equidigital number, since it uses as much as digits as its factorization.
172241214139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24192, while the sum is 37.
The spelling of 172241214139 in words is "one hundred seventy-two billion, two hundred forty-one million, two hundred fourteen thousand, one hundred thirty-nine".
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