Base | Representation |
---|---|
bin | 10100100111011… |
… | …10010001100001 |
3 | 110001102101102022 |
4 | 22103232101201 |
5 | 323233124213 |
6 | 25054431225 |
7 | 4166662226 |
oct | 1223562141 |
9 | 401371368 |
10 | 172942433 |
11 | 89692234 |
12 | 49b02515 |
13 | 29aa2701 |
14 | 18d7b94d |
15 | 102b2308 |
hex | a4ee461 |
172942433 has 2 divisors, whose sum is σ = 172942434. Its totient is φ = 172942432.
The previous prime is 172942417. The next prime is 172942489. The reversal of 172942433 is 334249271.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124389409 + 48553024 = 11153^2 + 6968^2 .
It is a cyclic number.
It is not a de Polignac number, because 172942433 - 24 = 172942417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 172942393 and 172942402.
It is not a weakly prime, because it can be changed into another prime (172942333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86471216 + 86471217.
It is an arithmetic number, because the mean of its divisors is an integer number (86471217).
Almost surely, 2172942433 is an apocalyptic number.
It is an amenable number.
172942433 is a deficient number, since it is larger than the sum of its proper divisors (1).
172942433 is an equidigital number, since it uses as much as digits as its factorization.
172942433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36288, while the sum is 35.
The square root of 172942433 is about 13150.7578869052. The cubic root of 172942433 is about 557.1436539828.
The spelling of 172942433 in words is "one hundred seventy-two million, nine hundred forty-two thousand, four hundred thirty-three".
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