Search a number
-
+
172952389433 is a prime number
BaseRepresentation
bin1010000100010011000…
…1000000011100111001
3121112102100102201001002
42201010301000130321
510313201302430213
6211241521534345
715331631024345
oct2410461003471
9545370381032
10172952389433
116739212a03a
12296294a43b5
131340380b995
148529c08625
154773b37658
hex2844c40739

172952389433 has 2 divisors, whose sum is σ = 172952389434. Its totient is φ = 172952389432.

The previous prime is 172952389427. The next prime is 172952389459. The reversal of 172952389433 is 334983259271.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 165639232144 + 7313157289 = 406988^2 + 85517^2 .

It is an emirp because it is prime and its reverse (334983259271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172952389433 - 210 = 172952388409 is a prime.

It is a super-2 number, since 2×1729523894332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (172952889433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86476194716 + 86476194717.

It is an arithmetic number, because the mean of its divisors is an integer number (86476194717).

Almost surely, 2172952389433 is an apocalyptic number.

It is an amenable number.

172952389433 is a deficient number, since it is larger than the sum of its proper divisors (1).

172952389433 is an equidigital number, since it uses as much as digits as its factorization.

172952389433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9797760, while the sum is 56.

The spelling of 172952389433 in words is "one hundred seventy-two billion, nine hundred fifty-two million, three hundred eighty-nine thousand, four hundred thirty-three".