Base | Representation |
---|---|
bin | 1010000101000000000… |
… | …0011011011100101111 |
3 | 121112220111022011210100 |
4 | 2201100000123130233 |
5 | 10314043042402201 |
6 | 211312340042143 |
7 | 15336411026526 |
oct | 2412000333457 |
9 | 545814264710 |
10 | 173140981551 |
11 | 6747963009a |
12 | 29680693353 |
13 | 13433900655 |
14 | 8546c9b4bd |
15 | 478548b886 |
hex | 285001b72f |
173140981551 has 12 divisors (see below), whose sum is σ = 250801010928. Its totient is φ = 115100329344.
The previous prime is 173140981511. The next prime is 173140981553. The reversal of 173140981551 is 155189041371.
173140981551 is a `hidden beast` number, since 1 + 7 + 3 + 1 + 4 + 0 + 98 + 1 + 551 = 666.
It is not a de Polignac number, because 173140981551 - 27 = 173140981423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 173140981497 and 173140981506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (173140981553) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27245955 + ... + 27252308.
It is an arithmetic number, because the mean of its divisors is an integer number (20900084244).
Almost surely, 2173140981551 is an apocalyptic number.
173140981551 is a deficient number, since it is larger than the sum of its proper divisors (77660029377).
173140981551 is a wasteful number, since it uses less digits than its factorization.
173140981551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54498622 (or 54498619 counting only the distinct ones).
The product of its (nonzero) digits is 151200, while the sum is 45.
The spelling of 173140981551 in words is "one hundred seventy-three billion, one hundred forty million, nine hundred eighty-one thousand, five hundred fifty-one".
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