Base | Representation |
---|---|
bin | 10000001100100001… |
… | …011110001011000001 |
3 | 1122212221022000100011 |
4 | 100030201132023001 |
5 | 241103313020423 |
6 | 11553331224521 |
7 | 1153640210215 |
oct | 201441361301 |
9 | 48787260304 |
10 | 17389970113 |
11 | 7414203a2a |
12 | 3453a48141 |
13 | 1841a32659 |
14 | bad7d2945 |
15 | 6bba58b0d |
hex | 40c85e2c1 |
17389970113 has 2 divisors, whose sum is σ = 17389970114. Its totient is φ = 17389970112.
The previous prime is 17389970093. The next prime is 17389970119. The reversal of 17389970113 is 31107998371.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14178141184 + 3211828929 = 119072^2 + 56673^2 .
It is a cyclic number.
It is not a de Polignac number, because 17389970113 - 29 = 17389969601 is a prime.
It is a super-2 number, since 2×173899701132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (17389970119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8694985056 + 8694985057.
It is an arithmetic number, because the mean of its divisors is an integer number (8694985057).
Almost surely, 217389970113 is an apocalyptic number.
It is an amenable number.
17389970113 is a deficient number, since it is larger than the sum of its proper divisors (1).
17389970113 is an equidigital number, since it uses as much as digits as its factorization.
17389970113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 285768, while the sum is 49.
The spelling of 17389970113 in words is "seventeen billion, three hundred eighty-nine million, nine hundred seventy thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •