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174130448137 is a prime number
BaseRepresentation
bin1010001000101011111…
…0111100011100001001
3121122110110011021202221
42202022332330130021
510323104343320022
6211554443454041
715403054250002
oct2421276743411
9548413137687
10174130448137
1167937109a78
12298b7b27321
13135608c0239
1485dc4661a9
1547e228bcc7
hex288afbc709

174130448137 has 2 divisors, whose sum is σ = 174130448138. Its totient is φ = 174130448136.

The previous prime is 174130448131. The next prime is 174130448221. The reversal of 174130448137 is 731844031471.

174130448137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142584780816 + 31545667321 = 377604^2 + 177611^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-174130448137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 174130448093 and 174130448102.

It is not a weakly prime, because it can be changed into another prime (174130448131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87065224068 + 87065224069.

It is an arithmetic number, because the mean of its divisors is an integer number (87065224069).

Almost surely, 2174130448137 is an apocalyptic number.

It is an amenable number.

174130448137 is a deficient number, since it is larger than the sum of its proper divisors (1).

174130448137 is an equidigital number, since it uses as much as digits as its factorization.

174130448137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225792, while the sum is 43.

The spelling of 174130448137 in words is "one hundred seventy-four billion, one hundred thirty million, four hundred forty-eight thousand, one hundred thirty-seven".