Base | Representation |
---|---|
bin | 11001100000110000101… |
… | …101111001111110111001 |
3 | 20012121020000100200221002 |
4 | 121200300231321332321 |
5 | 212210434440401423 |
6 | 3421220432454345 |
7 | 240443016045464 |
oct | 31406055717671 |
9 | 6177200320832 |
10 | 1753163997113 |
11 | 61657040a491 |
12 | 2439370aa3b5 |
13 | c9426b49929 |
14 | 60bd43742db |
15 | 3090cd4e228 |
hex | 19830b79fb9 |
1753163997113 has 2 divisors, whose sum is σ = 1753163997114. Its totient is φ = 1753163997112.
The previous prime is 1753163997097. The next prime is 1753163997139. The reversal of 1753163997113 is 3117993613571.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1254328321024 + 498835676089 = 1119968^2 + 706283^2 .
It is a cyclic number.
It is not a de Polignac number, because 1753163997113 - 24 = 1753163997097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1753163997163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 876581998556 + 876581998557.
It is an arithmetic number, because the mean of its divisors is an integer number (876581998557).
Almost surely, 21753163997113 is an apocalyptic number.
It is an amenable number.
1753163997113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1753163997113 is an equidigital number, since it uses as much as digits as its factorization.
1753163997113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3214890, while the sum is 56.
The spelling of 1753163997113 in words is "one trillion, seven hundred fifty-three billion, one hundred sixty-three million, nine hundred ninety-seven thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •