Base | Representation |
---|---|
bin | 10000011110010111… |
… | …101100111101010001 |
3 | 1200122210201120201102 |
4 | 100132113230331101 |
5 | 242211441232441 |
6 | 12043145114145 |
7 | 1164234261122 |
oct | 203627547521 |
9 | 50583646642 |
10 | 17689399121 |
11 | 7558228419 |
12 | 3518188955 |
13 | 188ba90594 |
14 | bdb498049 |
15 | 6d7ea369b |
hex | 41e5ecf51 |
17689399121 has 2 divisors, whose sum is σ = 17689399122. Its totient is φ = 17689399120.
The previous prime is 17689399099. The next prime is 17689399151. The reversal of 17689399121 is 12199398671.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10547290000 + 7142109121 = 102700^2 + 84511^2 .
It is a cyclic number.
It is not a de Polignac number, because 17689399121 - 218 = 17689136977 is a prime.
It is not a weakly prime, because it can be changed into another prime (17689399151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8844699560 + 8844699561.
It is an arithmetic number, because the mean of its divisors is an integer number (8844699561).
Almost surely, 217689399121 is an apocalyptic number.
It is an amenable number.
17689399121 is a deficient number, since it is larger than the sum of its proper divisors (1).
17689399121 is an equidigital number, since it uses as much as digits as its factorization.
17689399121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1469664, while the sum is 56.
The spelling of 17689399121 in words is "seventeen billion, six hundred eighty-nine million, three hundred ninety-nine thousand, one hundred twenty-one".
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