Base | Representation |
---|---|
bin | 1000001011100110001010… |
… | …01111100111100010101001 |
3 | 2100200212222002112012121112 |
4 | 10011303011033213202221 |
5 | 4324224303323210241 |
6 | 102132440553320105 |
7 | 3534531431622665 |
oct | 405630517474251 |
9 | 70625862465545 |
10 | 17990632241321 |
11 | 5806869981533 |
12 | 2026856406035 |
13 | a06681038cbc |
14 | 462a735c58a5 |
15 | 212e9e7861eb |
hex | 105cc53e78a9 |
17990632241321 has 2 divisors, whose sum is σ = 17990632241322. Its totient is φ = 17990632241320.
The previous prime is 17990632241251. The next prime is 17990632241353. The reversal of 17990632241321 is 12314223609971.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16127966849296 + 1862665392025 = 4015964^2 + 1364795^2 .
It is a cyclic number.
It is not a de Polignac number, because 17990632241321 - 214 = 17990632224937 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 17990632241321.
It is not a weakly prime, because it can be changed into another prime (17990632441321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8995316120660 + 8995316120661.
It is an arithmetic number, because the mean of its divisors is an integer number (8995316120661).
Almost surely, 217990632241321 is an apocalyptic number.
It is an amenable number.
17990632241321 is a deficient number, since it is larger than the sum of its proper divisors (1).
17990632241321 is an equidigital number, since it uses as much as digits as its factorization.
17990632241321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 17990632241321 in words is "seventeen trillion, nine hundred ninety billion, six hundred thirty-two million, two hundred forty-one thousand, three hundred twenty-one".
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