Base | Representation |
---|---|
bin | 1000001100000011100011… |
… | …10111000011001011010011 |
3 | 2100202101200220002222221111 |
4 | 10012001301313003023103 |
5 | 4330004113232124141 |
6 | 102144010525234151 |
7 | 3535630463340451 |
oct | 406016167031323 |
9 | 70671626088844 |
10 | 18006413161171 |
11 | 5812527892156 |
12 | 202991b402957 |
13 | a07cc75b73b6 |
14 | 46372d4099d1 |
15 | 2135c4e04381 |
hex | 106071dc32d3 |
18006413161171 has 2 divisors, whose sum is σ = 18006413161172. Its totient is φ = 18006413161170.
The previous prime is 18006413161117. The next prime is 18006413161193. The reversal of 18006413161171 is 17116131460081.
Together with previous prime (18006413161117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (17116131460081) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 18006413161171 - 225 = 18006379606739 is a prime.
It is not a weakly prime, because it can be changed into another prime (18006413161571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9003206580585 + 9003206580586.
It is an arithmetic number, because the mean of its divisors is an integer number (9003206580586).
Almost surely, 218006413161171 is an apocalyptic number.
18006413161171 is a deficient number, since it is larger than the sum of its proper divisors (1).
18006413161171 is an equidigital number, since it uses as much as digits as its factorization.
18006413161171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 40.
The spelling of 18006413161171 in words is "eighteen trillion, six billion, four hundred thirteen million, one hundred sixty-one thousand, one hundred seventy-one".
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