Base | Representation |
---|---|
bin | 11010010110101011001… |
… | …110100000000000001011 |
3 | 20102010122110111022212211 |
4 | 122112223032200000023 |
5 | 214133014301433101 |
6 | 3503553043045551 |
7 | 244562414315431 |
oct | 32265316400013 |
9 | 6363573438784 |
10 | 1811053936651 |
11 | 639077807923 |
12 | 252bb23708b7 |
13 | 101a213a5a1b |
14 | 639268bcd51 |
15 | 3219a1edc51 |
hex | 1a5ab3a000b |
1811053936651 has 2 divisors, whose sum is σ = 1811053936652. Its totient is φ = 1811053936650.
The previous prime is 1811053936631. The next prime is 1811053936669. The reversal of 1811053936651 is 1566393501181.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1811053936651 - 217 = 1811053805579 is a prime.
It is a super-2 number, since 2×18110539366512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1811053936595 and 1811053936604.
It is not a weakly prime, because it can be changed into another prime (1811053936621) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 905526968325 + 905526968326.
It is an arithmetic number, because the mean of its divisors is an integer number (905526968326).
Almost surely, 21811053936651 is an apocalyptic number.
1811053936651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1811053936651 is an equidigital number, since it uses as much as digits as its factorization.
1811053936651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 49.
The spelling of 1811053936651 in words is "one trillion, eight hundred eleven billion, fifty-three million, nine hundred thirty-six thousand, six hundred fifty-one".
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