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181214113 is a prime number
BaseRepresentation
bin10101100110100…
…01101110100001
3110121222122000211
422303101232201
5332342322423
625552014121
74330203013
oct1263215641
9417878024
10181214113
1193321933
1250831341
132b70a6b2
141a0d21b3
1510d9810d
hexacd1ba1

181214113 has 2 divisors, whose sum is σ = 181214114. Its totient is φ = 181214112.

The previous prime is 181214063. The next prime is 181214129. The reversal of 181214113 is 311412181.

181214113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 155326369 + 25887744 = 12463^2 + 5088^2 .

It is a cyclic number.

It is not a de Polignac number, because 181214113 - 29 = 181213601 is a prime.

It is not a weakly prime, because it can be changed into another prime (181212113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 90607056 + 90607057.

It is an arithmetic number, because the mean of its divisors is an integer number (90607057).

Almost surely, 2181214113 is an apocalyptic number.

It is an amenable number.

181214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

181214113 is an equidigital number, since it uses as much as digits as its factorization.

181214113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192, while the sum is 22.

The square root of 181214113 is about 13461.5791421363. The cubic root of 181214113 is about 565.8882449470. Note that the first 3 decimals are identical.

Adding to 181214113 its reverse (311412181), we get a palindrome (492626294).

The spelling of 181214113 in words is "one hundred eighty-one million, two hundred fourteen thousand, one hundred thirteen".