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1814000055953 is a prime number
BaseRepresentation
bin11010011001011010110…
…101000011011010010001
320102102020210010200210112
4122121122311003122101
5214210033003242303
63505201244411105
7245025420031511
oct32313265033221
96372223120715
101814000055953
1163a349816968
12253694b46a95
131020a0873697
1463b25c9b841
15322bdb9d0d8
hex1a65ad43691

1814000055953 has 2 divisors, whose sum is σ = 1814000055954. Its totient is φ = 1814000055952.

The previous prime is 1814000055913. The next prime is 1814000055971. The reversal of 1814000055953 is 3595500004181.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1365934487824 + 448065568129 = 1168732^2 + 669377^2 .

It is a cyclic number.

It is not a de Polignac number, because 1814000055953 - 216 = 1813999990417 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1814000055953.

It is not a weakly prime, because it can be changed into another prime (1814000055913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 907000027976 + 907000027977.

It is an arithmetic number, because the mean of its divisors is an integer number (907000027977).

Almost surely, 21814000055953 is an apocalyptic number.

It is an amenable number.

1814000055953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1814000055953 is an equidigital number, since it uses as much as digits as its factorization.

1814000055953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 41.

The spelling of 1814000055953 in words is "one trillion, eight hundred fourteen billion, fifty-five thousand, nine hundred fifty-three".