Base | Representation |
---|---|
bin | 1000001111111110111000… |
… | …01110110001010001000011 |
3 | 2101020021222022001111212212 |
4 | 10013333130032301101003 |
5 | 4334211431442002324 |
6 | 102330003425212335 |
7 | 3551445234411443 |
oct | 407773416612103 |
9 | 71207868044785 |
10 | 18141341750339 |
11 | 5864777524275 |
12 | 204bab67910ab |
13 | a1794b5a6a82 |
14 | 46a08d2a8123 |
15 | 216d707b570e |
hex | 107fdc3b1443 |
18141341750339 has 2 divisors, whose sum is σ = 18141341750340. Its totient is φ = 18141341750338.
The previous prime is 18141341750333. The next prime is 18141341750347. The reversal of 18141341750339 is 93305714314181.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 18141341750339 - 232 = 18137046783043 is a prime.
It is a super-2 number, since 2×181413417503392 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (18141341750333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9070670875169 + 9070670875170.
It is an arithmetic number, because the mean of its divisors is an integer number (9070670875170).
Almost surely, 218141341750339 is an apocalyptic number.
18141341750339 is a deficient number, since it is larger than the sum of its proper divisors (1).
18141341750339 is an equidigital number, since it uses as much as digits as its factorization.
18141341750339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 18141341750339 in words is "eighteen trillion, one hundred forty-one billion, three hundred forty-one million, seven hundred fifty thousand, three hundred thirty-nine".
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