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1815997496473 is a prime number
BaseRepresentation
bin11010011011010001111…
…000101011110010011001
320102121101222200012002001
4122123101320223302121
5214223130324341343
63510131400441001
7245126053013326
oct32332170536231
96377358605061
101815997496473
11640184275556
12253b51a79161
1310232b632a54
1463c7528bb4d
153238920744d
hex1a6d1e2bc99

1815997496473 has 2 divisors, whose sum is σ = 1815997496474. Its totient is φ = 1815997496472.

The previous prime is 1815997496441. The next prime is 1815997496477. The reversal of 1815997496473 is 3746947995181.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1643413749849 + 172583746624 = 1281957^2 + 415432^2 .

It is a cyclic number.

It is not a de Polignac number, because 1815997496473 - 25 = 1815997496441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1815997496396 and 1815997496405.

It is not a weakly prime, because it can be changed into another prime (1815997496477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 907998748236 + 907998748237.

It is an arithmetic number, because the mean of its divisors is an integer number (907998748237).

Almost surely, 21815997496473 is an apocalyptic number.

It is an amenable number.

1815997496473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1815997496473 is an equidigital number, since it uses as much as digits as its factorization.

1815997496473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 411505920, while the sum is 73.

The spelling of 1815997496473 in words is "one trillion, eight hundred fifteen billion, nine hundred ninety-seven million, four hundred ninety-six thousand, four hundred seventy-three".